Ruby vs Java

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Blog » Ruby vs Java

Posted on 1244240985|%A: %d %B, %Y|agohover

I defend my point! This is the Ruby code

a = gets.to_i
b = gets.to_i
c = a + b
puts c

And this is the corresponding Java code

import java.io.*;
public class Addup
{
    static public void main(String args[])  {
        InputStreamReader stdin = new InputStreamReader(System.in);
        BufferedReader console = new BufferedReader(stdin);
        int i1 = 0,i2 = 0;
        String s1,s2;
        try {
            s1 = console.readLine();
            i1 = Integer.parseInt(s1);
            s2 = console.readLine();
            i2 = Integer.parseInt(s2);
        }
        catch(IOException ioex) {
            System.out.println("Input error");
            System.exit(1);
        }
        catch(NumberFormatException nfex) {
            System.out.println("\"" + nfex.getMessage() + "\" is not numeric");
            System.exit(1);
        }
        System.out.println(i1 + " + " + i2 + " = " + (i1+i2));
        System.exit(0);
    }
}
%> javac Addup.java
%> java Addup

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(Code blocks borrowed from http://www.ariel.com.au/a/teaching-programming.html)

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